Alexander finalizes deal with Seahawks:
The NFL's MVP agrees to a $62 million contract on the same day labor talks fizzle but prompt a new delay ................
Monday, March 06, 2006
NFL most valuable player Shaun Alexander has agreed to a $62 million, eight-year contract to remain with the Seattle Seahawks, his agent told The Associated Press by telephone Sunday night, minutes after the NFL pushed back the start of the free agent signing period 72 hours to Thursday.
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